0. Preliminaries.

Definition. A general trigonometric series is a formal mathematical expression written as

where is a sequence of complex numbers, called the coefficients, and is a real variable. The symbol ~ is used to denote that this is a formal series, and we make no initial assumptions about its convergence or its relationship to any function .

Definition. The N-th symmetric partial sum of the series is the function defined by the finite sum

The series is said to converge pointwise at a specific value if the sequence of complex numbers has a well-defined limit as .

1. Necessary Conditions and Divergence.

Before establishing conditions that guarantee convergence, we identify the most basic prerequisite. A series cannot converge if its individual terms do not shrink to nothing.

Theorem. If the series converges at a point , then the terms corresponding to indices and must jointly vanish as . Specifically,

Proof. Let be the sequence of partial sums. The hypothesis that the series converges at means that for some finite complex number .

  1. A convergent sequence is necessarily a Cauchy sequence. This implies that the difference between successive terms of the sequence must approach zero.

  2. We compute this difference explicitly from the definition of the partial sum:

    All terms except those with index and cancel, leaving

  3. Combining these two points yields the stated result.

Theorem 2 (Necessity of Decaying Coefficients). The condition is necessary for the series to converge on a set of positive measure.

Proof. Let the series converge on a set with Lebesgue measure . We first show the coefficient sequence is bounded, then show it converges to zero.

Step 1: The sequence is bounded. Assume for contradiction that is unbounded. Then there exists a subsequence of indices such that . By Theorem 1, for . By Egorov’s theorem, convergence is uniform on a subset with . The normalized functions also converge to 0 uniformly on . The coefficients of , namely and , satisfy . Uniform convergence implies . We expand the integral:

The sequences and are bounded. By the Riemann-Lebesgue lemma, . The last two terms thus vanish as . Taking the limit yields , a contradiction. The sequence must be bounded.

Step 2: The coefficients converge to zero. Assume for contradiction that . Then for some . There exists a subsequence with . As in Step 1, uniformly on a set with , which implies . The integral is:

From Step 1, is bounded, so is a bounded sequence. The Riemann-Lebesgue lemma ensures the integrals vanish. The last two terms thus tend to zero. Taking the limit gives . Since , this implies , contradicting that . Thus, .

Theorem (Kolmogorov). There exists a sequence with for which the series diverges for every .

Proof. The proof is a landmark result in harmonic analysis that involves the intricate construction of an function whose Fourier series diverges everywhere. This construction is highly advanced and is omitted. The significance of this theorem is profound: it demonstrates that there is no simple condition on the magnitude of the coefficients alone that can guarantee pointwise convergence for a general series.

2. Absolute and Uniform Convergence.

The strongest and most straightforward type of convergence occurs when the coefficients themselves are absolutely summable. This guarantees excellent behavior for the series.

Theorem (Weierstrass M-Test for Trigonometric Series). If the sequence of coefficients is absolutely summable, meaning , then the series converges absolutely and uniformly on to a function which is continuous.

Proof. The goal is to show that the sequence of functions converges uniformly. We work within the space of bounded, continuous functions on , denoted , which is a complete metric space (a Banach space) under the supremum norm, .

  1. Cauchy Sequence Argument: We show that is a Cauchy sequence in this space. Let . Consider the norm of the difference:

  2. Applying the Triangle Inequality: By the triangle inequality and the fact that :

  3. Using the Hypothesis: The hypothesis is that the series of real numbers converges. A convergent series must have a Cauchy sequence of partial sums. This means that for any , there exists an integer such that for all , the tail sum is small: .

  4. Conclusion: Combining these steps, for , we have . Thus, is a Cauchy sequence in the Banach space . Because the space is complete, the sequence must converge to a limit function . The uniform limit of a sequence of continuous functions (each is a finite sum of continuous functions, hence continuous) is itself continuous.

Theorem (Moment Conditions for Smoothness). Let be an integer. If the “k-th moment” of the coefficients is finite, i.e., , then the series converges uniformly to a function (meaning has continuous derivatives). Furthermore, these derivatives can be computed by term-by-term differentiation of the series.

Proof. We proceed by induction on .

  1. Base Case (k=1): We are given . Since for , the condition also holds. By the previous theorem, the series for converges uniformly to a continuous function . Now consider the formal series of derivatives:

    Let be its partial sums. The sum of the absolute values of the coefficients of this new series is . By hypothesis, this sum is finite. Applying the Weierstrass M-Test to this new series, we conclude that the functions converge uniformly to a continuous function . A fundamental theorem of analysis states that if converges to (even just pointwise) and the sequence of derivatives converges uniformly to , then must be differentiable and . Since is continuous, .

  2. Inductive Step: Assume the theorem holds for . Suppose . Let . The coefficients of this series are . We check the -th moment condition for this new series:

    This is finite by our hypothesis. By the inductive hypothesis, the series for converges to a function . Since , it follows that . The proof is complete by induction.

3. Conditional and Pointwise Convergence.

When absolute convergence fails, the series can still converge if the coefficients decay in a sufficiently structured manner. The key tool here is summation by parts.

Definition. A sequence of complex numbers is of bounded variation if the sum of the magnitudes of its successive differences is finite: .

Theorem (Jordan-Dirichlet Test). If the sequence of coefficients is of bounded variation and , then the series converges pointwise for every which is not an integer multiple of .

Proof. It suffices to prove the convergence of the sum over positive indices, , as the argument for negative indices is identical.

  1. Summation by Parts (Abel’s Transformation): Let . The formula for summation by parts states:

  2. Boundedness of the Dirichlet Sums: The sum is a finite geometric series. For , .

    Let . This bound is finite for our chosen and is independent of .

  3. Analyzing the Limit: We take the limit of the summation-by-parts formula as .

    • First Term: . Since by hypothesis, this term vanishes: .
    • Second Term: We examine the infinite series . We show it converges absolutely: This final sum is finite by the hypothesis that is of bounded variation. Since the series of absolute values converges, the series itself converges.
  4. Conclusion: Both terms on the right-hand side of the summation-by-parts formula have a well-defined limit. Therefore, the left-hand side must also converge.

4. L² and Almost Everywhere Convergence.

A paradigm shift in modern analysis was to consider convergence not at every point, but in an average sense, which requires tools from Hilbert space theory.

Theorem (Riesz-Fischer). Let the coefficients be square-summable, i.e., , meaning . Then there exists a unique function such that the partial sums converge to in the norm.

Proof. The space of square-integrable functions is a complete Hilbert space. The proof shows that is a Cauchy sequence in this space.

  1. Orthogonality: The basis functions are orthogonal over , satisfying .

  2. Computing the Norm of the Difference: For , we compute the squared -norm of the difference of partial sums:

    Due to orthogonality, the integral is zero unless , in which case it is .

  3. Result: The expression simplifies to:

  4. Conclusion: The hypothesis means that the tail of this real series must go to zero. Thus, for any , we can find so that for , . This shows is a Cauchy sequence in . By the completeness of the space, a limit function must exist.

Theorem (Carleson-Hunt). If , then the partial sums converge pointwise to the limit function for almost every .

Proof. The proof of this theorem, which settled a 50-year-old conjecture by Lusin, is one of the most complex and profound achievements in 20th-century mathematical analysis. It is far beyond the scope of this summary and is omitted. Its statement, however, is a beautiful bridge between the worlds of average () convergence and pointwise convergence.